WebFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. WebAug 16, 2024 · So to find sin (2A), based on the formula (1) above, we'll need to figure out the value of cosA. In this case since ∠A is in Q2, the value of cosA is negative. To figure out what cosA is, use your pythagorean identity: cosA = √ (1 - sin 2 A) = √ (1 - (4/5) 2) = √ (1 - 16/25) = √ (9/25) = 3/5 Since cosA is negative (since we're in Q2), cosA = -3/5
Solucionar =1/sqrt{2}text{and}cosB=sqrt{3}/2 Microsoft Math Solver
WebDouble-Angle and Half-Angle Formulas If sinA= (3)/ (5) with A in QH, find sin2A. Expert Answer 1st step All steps Final answer Step 1/1 Given that : sin A = 3 5 Find sin 2 A Solution: sin 2 A = 2 sin A cos A View the full answer Final answer Previous question Next question This problem has been solved! WebJan 25, 2024 · if sinA=2/5, and A is in the second quadrant, find cosA, cos2A, and sin2A. ... Math Algebra 2 Calculus Geometry Algebra Word Problem Pre Calculus Functions College Algebra Math Help... Trig Pre Calculus Precalculus Homework Mathematics Tangent Math Help For College Trigonometric Identities Trigonometric Functions Cosine … fraser coast 4wd recyclers
Sin2x - Formula, Identities, Examples, Proof Sin^2x Formula
Webthis because they involve trigonometric functions of double angles, i.e. sin2A, cos2A and tan2A. 2. The double angle formulae for sin2A,cos2A andtan2A We start by recalling the addition formulae which have already been described in the unit of the same name. sin(A+B) = sinAcosB +cosAsinB cos(A+B) = cosAcosB − sinAsinB tan(A+B) = tanA+tanB 1 ... WebDec 2, 2015 · Find tan 2A, given sinA = 3 5 and A in Quadrant II. Ans: − 24 7 Explanation: Use the trig identity: tan2A = 2tanA 1 − tan2A (1). First, find tanA = sinA cosA. sinA = 3 5 --> sin2A = 9 25 --> cos2A = 1 − 9 25 = 15 25 - --> cosA = ± 4 5. Because A is in Quadrant II, its cos is negative. cosA = − 4 5 tanA = sinA cosA = (3 5)( − 5 4) = − 3 4 WebAnswer: The value of sin2A = 4√5/9. Example 3: If tan A = 4/3, find the value of sin2A. Solution: We have sin 2x = 2tan (x) / (1 + tan 2 (x)) So sin 2A = 2tan (A) / (1 + tan 2 (A)) Putting the value of tan A = 4/3, we get Sin 2A = 2 (4/3) / (1 + (4/3) 2) Sin2A = (8/3)/ (25/9) Sin 2A = 24/25 Answer: sin 2A = 24/25. fraser clan schottland